3.7 Improper Integrals

[STARTS AT 23:08]

Instructor: Number 61. We go from 0 to 2 of 1 over x. All right. Well that's first going to be the limit as t goes to 0 from the right integral from t to 2 of 1 over x dx, which is limit as t goes to 0 from the right of the natural log, absolute value of x, evaluated from t to 2. Keep my limit. Evaluating on 2 natural log, absolute value of 2, which is just going to be 2. I don't need that. Integral log 2 minus natural log of t. Now is it comes from 0 from the right, this is going to is going to negative infinity. So actually, our answer here is going to be that it diverges this would be positive infinity. So our integral diverges to plus infinity. OK. 

[ENDS AT 24:28]