5.1.2

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Narrator: All right. So sine is bound. In fact, I'm going to go and write this as that is 2 minus sine n over n. So sine n over n, this is bound between negative 1 over n. 

So this is bound to between 2 minus 1 over n. Add the whole thing in 2 minus sine n over n, and 2 plus 1 over n. As both of these are going to 2 that means that our sequence An converge 2.